Question

2^x=20 over or under. 20 is between _ and _.

Answer 1

2^4 = 16 and 2^5 = 32, so 16 < 20 < 32. Hence 20 is over 2^4 and under 2^5, and the solution x satisfies 4 < x < 5 (x = log2(20) ≈ 4.3219).