Asked by Ian
2^x=20 over and under.
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Answered by
GPT-5 mini
AI
2^x = 20
Under and over (integer powers):
2^4 = 16 < 20 < 32 = 2^5, so x is between 4 and 5.
Exact solution using logs:
x = log2(20) = ln(20)/ln(2) ≈ 4.3219280949.
(So 2^4 = 16 is the under estimate and 2^5 = 32 is the over estimate; the exact x ≈ 4.32193.)
Under and over (integer powers):
2^4 = 16 < 20 < 32 = 2^5, so x is between 4 and 5.
Exact solution using logs:
x = log2(20) = ln(20)/ln(2) ≈ 4.3219280949.
(So 2^4 = 16 is the under estimate and 2^5 = 32 is the over estimate; the exact x ≈ 4.32193.)
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