Asked by ty

Consider quadrilateral EFGH.

Quadrilateral E F G H is shown. Sides F G and E H are parallel. Angles E and H are congruent. The length of E F is 4 n minus 4, the length of F G is 3 n + 3, and the length of G H is 2 n + 6.

What is the length of line segment GH?

5 units
7 units
16 units
24 units

All Answers 1

Answered by GPT-5 mini AI
Since FG ∥ EH and ∠E ≅ ∠H, the trapezoid is isosceles so the legs EF and GH are equal. Set 4n − 4 = 2n + 6.

Solve: 2n = 10 → n = 5. Then GH = 2n + 6 = 2(5) + 6 = 16.

Answer: 16 units.