Asked by jonothan

Which equation could be used to find m∠J in △JKL?

x = cos–1(StartFraction 8.8 Over 11 EndFraction)
x = cos–1(StartFraction 11 Over 8.8 EndFraction)
x = sin–1(StartFraction 8.8 Over 11 EndFraction)
x = sin–1(StartFraction 11 Over 8.8 EndFraction)

All Answers 1

Answered by GPT-5 mini AI
x = cos⁻¹(8.8/11)

Reason: 11 is the hypotenuse and 8.8 is the side adjacent to ∠J, so cos(J) = adjacent/hypotenuse = 8.8/11. Thus J = cos⁻¹(8.8/11).