Asked by j
Maryvale High School is starting a freshman mentoring program. There are eight seniors, twelve juniors, and four sophomores signed up to mentor. Ten mentors will be chosen for the school year.
Round answers to three decimal places.
What are the total number of ways to choose ten mentors from the group of seniors, juniors, and sophomores?
What is the probability that the mentors will be five seniors, three juniors, and two sophomores?
All Answers 1
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Total mentors = 8 + 12 + 4 = 24.
Total ways = C(24,10) = 1,961,256 ( = 1961256.000 to three decimals).
Favorable ways = C(8,5)·C(12,3)·C(4,2) = 56·220·6 = 73,920.
Probability = 73,920 / 1,961,256 ≈ 0.037690 → 0.038 (rounded to three decimal places).
Total ways = C(24,10) = 1,961,256 ( = 1961256.000 to three decimals).
Favorable ways = C(8,5)·C(12,3)·C(4,2) = 56·220·6 = 73,920.
Probability = 73,920 / 1,961,256 ≈ 0.037690 → 0.038 (rounded to three decimal places).
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