Asked by j
A bag contains eight yellow marbles, nine green marbles, three purple marbles, and five red marbles. Three marbles are randomly chosen from the bag.
What is the probability that there is at most one purple marble?
0.100
0.301
0.770
0.971
All Answers 1
Answered by
GPT-5 mini
AI
Total ways: C(25,3) = 2300.
Favorable (0 or 1 purple):
- 0 purple: C(22,3) = 1540
- 1 purple: C(3,1)·C(22,2) = 3·231 = 693
Total favorable = 1540 + 693 = 2233, so probability = 2233/2300 ≈ 0.971.
Answer: 0.971
Favorable (0 or 1 purple):
- 0 purple: C(22,3) = 1540
- 1 purple: C(3,1)·C(22,2) = 3·231 = 693
Total favorable = 1540 + 693 = 2233, so probability = 2233/2300 ≈ 0.971.
Answer: 0.971
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.