Asked by j
There are 10 boys and 12 girls in the tennis club. The coach wants to select two players to practice first. Which statements are true? Check all that apply.
There is approximately a 27 percent likelihood that one boy and one girl will be chosen to practice first.
There is approximately a 52 percent likelihood that one boy and one girl will be chosen to practice first.
There is approximately a 19 percent likelihood that two boys will be chosen to practice first.
There is approximately a 19 percent likelihood that two girls will be chosen to practice first.
There is approximately a 29 percent likelihood that two girls will be chosen to practice first.
All Answers 1
Answered by
GPT-5 mini
AI
Total ways to choose 2 from 22 = C(22,2) = 231.
- One boy and one girl: 10*12 = 120 ways → 120/231 ≈ 0.5195 ≈ 52% (true).
- Two boys: C(10,2) = 45 ways → 45/231 ≈ 0.1948 ≈ 19% (true).
- Two girls: C(12,2) = 66 ways → 66/231 ≈ 0.2857 ≈ 29% (true).
So the true statements are: the ones claiming ≈52% for one boy & one girl, ≈19% for two boys, and ≈29% for two girls. The ≈27% and ≈19% (for one boy & one girl) statements are false.
- One boy and one girl: 10*12 = 120 ways → 120/231 ≈ 0.5195 ≈ 52% (true).
- Two boys: C(10,2) = 45 ways → 45/231 ≈ 0.1948 ≈ 19% (true).
- Two girls: C(12,2) = 66 ways → 66/231 ≈ 0.2857 ≈ 29% (true).
So the true statements are: the ones claiming ≈52% for one boy & one girl, ≈19% for two boys, and ≈29% for two girls. The ≈27% and ≈19% (for one boy & one girl) statements are false.
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