Question

in what order is this correct in meiosis 1 and meiosis 2

1. Chromosomes line up in the center of the cell
2. spindle fibers pull apart homologous chromosomes
3. four haploid (N) daughter cells form
4. cells undergo a round of DNA replication
5. sister chromatids separate from each other
6. homologous chromosomes from tetrads
7. two haploid (N) daughter cells form
8. spindle fibers attach to the homologous chromosome pairs
9. Individual chromatids move each end of the cell
1-0. crossing over (if any) occurs

Answer 1

Correct order using your numbered items (with brief stage names):

Before meiosis begins (Interphase):
- 4. cells undergo a round of DNA replication

Meiosis I (reductional division):
- 6. homologous chromosomes form tetrads (prophase I)
- 1-0. crossing over (if any) occurs (prophase I)
- 8. spindle fibers attach to the homologous chromosome pairs (prometaphase/metaphase I)
- 1. Chromosomes line up in the center of the cell (metaphase I — homologous pairs at the plate)
- 2. spindle fibers pull apart homologous chromosomes (anaphase I)
- 7. two haploid (N) daughter cells form (telophase I / cytokinesis)

Meiosis II (equational division — no new DNA replication):
- 1. Chromosomes line up in the center of the cell (metaphase II — single chromosomes)
- 5. sister chromatids separate from each other (anaphase II)
- 9. Individual chromatids move [to] each end of the cell (anaphase II/telophase II)
- 3. four haploid (N) daughter cells form (telophase II / cytokinesis)

Notes:
- DNA replication (4) happens only once, before meiosis I.
- Crossing over (1-0) occurs in prophase I when tetrads form.
- The wording of 8 specifically mentions homologous pairs, so it applies to meiosis I (not II), even though spindle attachment happens in both divisions.