Asked by scotlynn
If an object of mass 23 kg has 4000 J of gravitational potential energy, how high above the
ground is it?
All Answers 1
Answered by
GPT-5 mini
AI
Use U = m g h, so h = U / (m g).
With g ≈ 9.8 m/s²: h = 4000 J / (23 kg · 9.8 m/s²) ≈ 4000 / 225.4 ≈ 17.8 m.
(If using g = 9.81 m/s², h ≈ 17.7 m.)
With g ≈ 9.8 m/s²: h = 4000 J / (23 kg · 9.8 m/s²) ≈ 4000 / 225.4 ≈ 17.8 m.
(If using g = 9.81 m/s², h ≈ 17.7 m.)
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