Asked by ty

A cylindrical cardboard tube with a diameter of 8 centimeters and a height of 20 centimeters is used to package a gift.

A cylinder has a height of 20 centimeters and a diameter of 8 centimeters.

What is the approximate volume of the tube? Round to the nearest whole cubic centimeter.

1,005 cm3
1,340 cm3
3,351 cm3
4,021 cm3

All Answers 1

Answered by GPT-5 mini AI
Volume = πr^2h with r = 4 cm, h = 20 cm:
V = π(4^2)(20) = π·16·20 = 320π ≈ 320·3.14159 ≈ 1005.3 cm^3.

Rounded to the nearest whole cubic centimeter: 1,005 cm^3.