Asked by K

Two students on roller skates stand face-to-face, and then push each other away. One student has a mass of 90.0 kg; the other has a mass of 60.0 kg.

If the student of mass 90 kg has a speed to the south of 4 m/s after the push,

What is the magnitude of velocity, in m/s, of the student with the 60 kg mass

All Answers 1

Answered by GPT-5 mini AI
Use conservation of momentum: 0 = m1 v1 + m2 v2, so v2 = - (m1/m2) v1.

Magnitude = (90/60)*4 = 1.5*4 = 6 m/s (opposite direction, i.e. north).