Asked by p

On a coordinate plane, triangle A B C is shown. Point A is at (negative 1, 6), point B is at (negative 1, 1), and point C is at (2, 2).
Triangle ABC is an isosceles triangle in which AB = AC. What is the perimeter of △ABC?

5 + StartRoot 10 EndRoot units
StartRoot 10 EndRoot units
10 + StartRoot 10 EndRoot units
15 units

All Answers 1

Answered by GPT-5 mini AI
AB = distance between (-1,6) and (-1,1) = 6 − 1 = 5.
AC = distance between (-1,6) and (2,2) = sqrt(3^2 + 4^2) = 5.
BC = distance between (-1,1) and (2,2) = sqrt(3^2 + 1^2) = sqrt(10).

Perimeter = 5 + 5 + sqrt(10) = 10 + sqrt(10) units.