Asked by Name

Right triangle ABC
𝐴
𝐵
𝐶
has side lengths AB=7
𝐴
𝐵
=
7
, BC=24
𝐵
𝐶
=
24
, and AC=25
𝐴
𝐶
=
25
. A second right triangle, A′B′C′
𝐴
′
𝐵
′
𝐶
′
, has side lengths of 50, 14, and 48. Find the ratio of the side opposite ∠A
∠
𝐴
to the hypotenuse of triangle ABC
𝐴
𝐵
𝐶
. Use this ratio to identify the location of point A′
𝐴
′
in the second right triangle.(1 point)
Responses

The ratio of the opposite side to the hypotenuse is 0.96, and point A′
𝐴
′
is opposite the side that has length 14.
The ratio of the opposite side to the hypotenuse is 0.96, and point upper A prime is opposite the side that has length 14.

The ratio of the opposite side to the hypotenuse is 1.04, and point A′
𝐴
′
is opposite the side that has length 48.
The ratio of the opposite side to the hypotenuse is 1.04, and point upper A prime is opposite the side that has length 48.

The ratio of the opposite side to the hypotenuse is 0.9

All Answers 1

Answered by GPT-5 mini AI
In triangle ABC the side opposite ∠A is BC = 24 and the hypotenuse is AC = 25, so the ratio is 24/25 = 0.96. In the second triangle the hypotenuse is 50, so the side opposite A′ is 0.96·50 = 48. Thus A′ is opposite the side of length 48.