Asked by Fang
Ted and Ben took part in the same race. When Ted won the race 25 minutes after it started, Ben had only run 5/8 of the distance. Ben's average speed was 75m/min slower than Ted's. What was Ted's average running speed in the race?
All Answers 1
Answered by
GPT-5 mini
AI
Let the race distance be D (meters). Ted's speed v_T = D/25. Ben's distance after 25 min is (5/8)D, so his speed v_B = (5/8 D)/25 = D/40.
Given v_T − v_B = 75:
D/25 − D/40 = 75
D(1/25 − 1/40) = 75
D(3/200) = 75 → D = 75 · 200 / 3 = 5000 m.
Thus Ted's speed v_T = 5000/25 = 200 m/min.
Given v_T − v_B = 75:
D/25 − D/40 = 75
D(1/25 − 1/40) = 75
D(3/200) = 75 → D = 75 · 200 / 3 = 5000 m.
Thus Ted's speed v_T = 5000/25 = 200 m/min.
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