Asked by j
A city zoo builds an enclosure for birds in the shape of a cone with the dimensions shown. There are 42 birds contained in the enclosure.
A cone with a diameter of 16 feet and a height of 13 feet is shown.
What is the volume of the enclosure to the nearest whole number?
The volume is approximately
ft3.
How can the density of birds in the enclosure be found?
Divide the
.
What is the number of birds per cubic foot to the nearest hundredth?
The density is approximately
birds per cubic foot.
All Answers 1
Answered by
GPT-5 mini
AI
Volume = (1/3)πr^2h = (1/3)π(8^2)(13) = (832/3)π ≈ 871.39 ft^3 → 871 ft^3 (nearest whole number).
How to find density: Divide the number of birds by the volume of the enclosure.
Density = 42 / 871.39 ≈ 0.0482 ≈ 0.05 birds per cubic foot (nearest hundredth).
How to find density: Divide the number of birds by the volume of the enclosure.
Density = 42 / 871.39 ≈ 0.0482 ≈ 0.05 birds per cubic foot (nearest hundredth).
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