Asked by John

Figure this out.

P 4
P=

H 2
H=

F 6
F=

CH 4
C=
H=

CaBr 2
Ca=
Br=

2 H 2 O 2
H=
O=

3 NaOH
Na=
O=
H=

Na 2 SO 4
Na =
S =
O=

3 Mg(NO 3 ) 2
Mg =
N =
O =

2 NaOH
Na =
O =
H =

3 Al 2 (SO 4 ) 3
Al =
S =
O =

4 LiNO 3
Li =
N =
O =

____N 2 + ____H 2 �� ____ NH 3

N = N=
H= H=

____NaBr + _____CaF 2 �� ____NaF + ____CaBr 2
Na = Na =
Br = Br =
Ca = Ca =
F = F =
____AlBr 3 + ____K 2 SO 4 �� ____ KBr + ____Al 2 (SO 4 ) 3
Al = Al =
Br= Br =
K= K =
S= S =
O= O =
____CH 4 + ____O 2 �� ____CO 2 + ____H 2 O
C = C =
H = H =
O = O =
Na 3 PO 4 + 3 KOH �� 3 NaOH + K 3 PO 4 Reaction Type _____________________
MgCl 2 + Li 2 CO 3 �� MgCO 3 + 2 LiCl Reaction Type _____________________
C 6 H 12 + 9 O 2 �� 6 CO 2 + 6 H 2 O Reaction Type _____________________
Pb + FeSO 4 �� PbSO 4 + Fe Reaction Type _____________________
CaCO 3 �� CaO + CO 2 Reaction Type _____________________
P 4 + 3 O 2 �� 2 P 2 O 3 Reaction Type _____________________
2 RbNO 3 + BeF 2 �� Be(NO 3 ) 2 + 2 RbF Reaction Type _____________________

All Answers 1

Answered by GPT-5 mini AI
P4
P = 4

H2
H = 2

F6
F = 6

CH4
C = 1
H = 4

CaBr2
Ca = 1
Br = 2

2 H2O2
H = 4
O = 4

3 NaOH
Na = 3
O = 3
H = 3

Na2SO4
Na = 2
S = 1
O = 4

3 Mg(NO3)2
Mg = 3
N = 6
O = 18

2 NaOH
Na = 2
O = 2
H = 2

3 Al2(SO4)3
Al = 6
S = 9
O = 36

4 LiNO3
Li = 4
N = 4
O = 12

Balanced equations and atom counts:

N2 + 3 H2 → 2 NH3
N left = 2, N right = 2
H left = 6, H right = 6

2 NaBr + CaF2 → 2 NaF + CaBr2
Na left = 2, Na right = 2
Br left = 2, Br right = 2
Ca left = 1, Ca right = 1
F left = 2, F right = 2

2 AlBr3 + 3 K2SO4 → 6 KBr + Al2(SO4)3
Al left = 2, Al right = 2
Br left = 6, Br right = 6
K left = 6, K right = 6
S left = 3, S right = 3
O left = 12, O right = 12

CH4 + 2 O2 → CO2 + 2 H2O
C left = 1, C right = 1
H left = 4, H right = 4
O left = 4, O right = 4

Reaction types:

Na3PO4 + 3 KOH → 3 NaOH + K3PO4
Reaction type: double displacement (metathesis)

MgCl2 + Li2CO3 → MgCO3 + 2 LiCl
Reaction type: double displacement (precipitation)

C6H12 + 9 O2 → 6 CO2 + 6 H2O
Reaction type: combustion

Pb + FeSO4 → PbSO4 + Fe
Reaction type: single displacement (redox)

CaCO3 → CaO + CO2
Reaction type: decomposition

P4 + 3 O2 → 2 P2O3
Reaction type: synthesis (combination)

2 RbNO3 + BeF2 → Be(NO3)2 + 2 RbF
Reaction type: double displacement