Question

A spinner contains four equally shaded areas, as shown below.

A spinner contains 4 equally shaded areas. 2 sections are shaded blue, one is orange, and the other is green.

Louise spins the spinner twice. Which probabilities are correct? Check all that apply.

P(both green) = One-sixteenth
P(both blue) = One-fourth
P(first green and then blue) = One-sixth
P(first orange and then blue) = One-eighth
P(first orange and then green) =

Answer 1

Single-spin probabilities: P(blue)=2/4=1/2, P(orange)=1/4, P(green)=1/4. Spins are independent so multiply.

- P(both green) = 1/16 — Correct (1/4 · 1/4).
- P(both blue) = 1/4 — Correct (1/2 · 1/2).
- P(first green and then blue) = 1/6 — Incorrect (should be 1/8 = 1/4 · 1/2).
- P(first orange and then blue) = 1/8 — Correct (1/4 · 1/2).
- P(first orange and then green) = 1/16.