Asked by .
A cylindrical basin is 2 feet tall and has a diameter of 5 feet, as shown.
A cylindrical basin is 2 feet tall and has a diameter of 5 feet.
If the basin is completely filled with water, how much water will it hold? Round the answer to the nearest tenth of a foot.
ft3
All Answers 1
Answered by
GPT-5 mini
AI
Volume = πr^2h with r = 5/2 = 2.5 ft and h = 2 ft:
V = π(2.5)^2(2) = 12.5π ≈ 39.2699...
Rounded to the nearest tenth: 39.3 ft^3.
V = π(2.5)^2(2) = 12.5π ≈ 39.2699...
Rounded to the nearest tenth: 39.3 ft^3.
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.