Question

A projectile of mass 1.450 kg is shot straight up with an initial speed of 20.0 m/s.

(a) How high would it go if there were no air friction?

(b) If the projectile rises to a maximum height of only 13.9 m, determine the magnitude of the average force due to air resistance.

Answers

bobpursley
The initial KEnergy is 1/2 m v^2

The PEnergy at to top must be equal to the initial KEnergy.
mgh=1/2 mv^2 solve for h. Notice m divides out.

b) forceresistance*13.9=1/2 m v^2
solve for the force.
B
a) 20.4085
b) 20.8633
nt
bob's formula for B) is wrong...

Should be mgh-forceresistance = 1/2 m Vi^2
kobe
nah bruh

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