Asked by joshua
A projectile of mass 1.450 kg is shot straight up with an initial speed of 20.0 m/s.
(a) How high would it go if there were no air friction?
(b) If the projectile rises to a maximum height of only 13.9 m, determine the magnitude of the average force due to air resistance.
(a) How high would it go if there were no air friction?
(b) If the projectile rises to a maximum height of only 13.9 m, determine the magnitude of the average force due to air resistance.
Answers
Answered by
bobpursley
The initial KEnergy is 1/2 m v^2
The PEnergy at to top must be equal to the initial KEnergy.
mgh=1/2 mv^2 solve for h. Notice m divides out.
b) forceresistance*13.9=1/2 m v^2
solve for the force.
The PEnergy at to top must be equal to the initial KEnergy.
mgh=1/2 mv^2 solve for h. Notice m divides out.
b) forceresistance*13.9=1/2 m v^2
solve for the force.
Answered by
B
a) 20.4085
b) 20.8633
b) 20.8633
Answered by
nt
bob's formula for B) is wrong...
Should be mgh-forceresistance = 1/2 m Vi^2
Should be mgh-forceresistance = 1/2 m Vi^2
Answered by
kobe
nah bruh
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