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How much work is done when Snow lifts a 6kg apple 1.3 meters?
(2 parts) Givens:
Formula:
Sub #s and Solve:
Formula:
Sub #s and Solve:
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Givens:
- m = 6.0 kg
- h = 1.3 m
- g = 9.8 m/s²
Part 1 — Work done by Snow (lifting force):
- Formula: W = F·d = (m g) h
- Substitute & solve: W = (6.0 kg)(9.8 m/s²)(1.3 m) = 76.44 J ≈ 7.6 × 10¹ J
Part 2 — Work done by gravity (weight) during the lift:
- Formula: W_gravity = −m g h (opposite direction to displacement)
- Substitute & solve: W_gravity = −(6.0)(9.8)(1.3) = −76.44 J ≈ −7.6 × 10¹ J
(Positive value = work done by Snow on the apple; negative = work done by gravity.)
- m = 6.0 kg
- h = 1.3 m
- g = 9.8 m/s²
Part 1 — Work done by Snow (lifting force):
- Formula: W = F·d = (m g) h
- Substitute & solve: W = (6.0 kg)(9.8 m/s²)(1.3 m) = 76.44 J ≈ 7.6 × 10¹ J
Part 2 — Work done by gravity (weight) during the lift:
- Formula: W_gravity = −m g h (opposite direction to displacement)
- Substitute & solve: W_gravity = −(6.0)(9.8)(1.3) = −76.44 J ≈ −7.6 × 10¹ J
(Positive value = work done by Snow on the apple; negative = work done by gravity.)
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