Question

how much work is done to lift the jewel? Givens:
Formula:
Sub #s and Solve:

Answer 1

I don’t see the numerical givens in your message. Tell me the mass (or the lifting force) and the vertical distance (or the force and displacement and angle) and I’ll compute it. Meanwhile here’s the general approach and an example.

1) Formula (vertical lift at constant speed / against gravity):
W = F · d = m g h
where
- W is work (Joules),
- m is mass (kg),
- g ≈ 9.8 m/s² (acceleration due to gravity),
- h is vertical height (m).

2) Substitution template:
W = (m in kg) × (9.8 m/s²) × (h in m)

3) Example:
If m = 0.05 kg (50 g) and h = 2.0 m,
W = 0.05 × 9.8 × 2.0 = 0.98 J.

4) Other cases:
- If you know the constant force F (N) and displacement d (m) at angle θ to the displacement: W = F d cosθ.
- If mass given in grams, convert to kg (1000 g = 1 kg).
- If lifting with acceleration, include net force: W = (m(a+g))h for work done by the lifter (but change in gravitational potential still mgh).

Give me the specific numbers (mass or force, height or displacement and angle) and I’ll plug them in and solve.