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10. . a) How much force does Doc use while lifting a 100kg diamond 20 meters?
Givens:
Formula:
Sub #s and Solve:
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Givens:
- m = 100 kg
- h = 20 m
- g = 9.8 m/s² (standard)
Formula (force required to hold or lift at constant velocity):
- F = m g
Substitute and solve:
- F = (100 kg)(9.8 m/s²) = 980 N
(If you meant the work done lifting 20 m:)
- W = F · h = 980 N · 20 m = 19,600 J
Notes:
- The 980 N is the upward force needed to oppose gravity if Doc lifts at constant speed. If Doc accelerates upward, the required force would be larger. If you prefer g ≈ 10 m/s², then F ≈ 1000 N and W ≈ 20,000 J.
- m = 100 kg
- h = 20 m
- g = 9.8 m/s² (standard)
Formula (force required to hold or lift at constant velocity):
- F = m g
Substitute and solve:
- F = (100 kg)(9.8 m/s²) = 980 N
(If you meant the work done lifting 20 m:)
- W = F · h = 980 N · 20 m = 19,600 J
Notes:
- The 980 N is the upward force needed to oppose gravity if Doc lifts at constant speed. If Doc accelerates upward, the required force would be larger. If you prefer g ≈ 10 m/s², then F ≈ 1000 N and W ≈ 20,000 J.
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