Question

The length of a rectangle is four times the width. The perimeter of the rectangle is 45 inches. Write a system of equations that represents this problem. What is the area of the rectangle?


WRITER

Answer 1

Let width = w inches and length = l inches.

System:
1) l = 4w
2) 2l + 2w = 45

Solve by substitution: 2(4w) + 2w = 45 → 8w + 2w = 45 → 10w = 45 → w = 4.5 in.
Then l = 4w = 18 in.

Area = l·w = 18 · 4.5 = 81 square inches.