Asked by maxx
Which polynomial is prime?
x3 + 3x2 + 2x + 6
x3 + 3x2 – 2x – 6
10x2 – 4x + 3x + 6
10x2 – 10x + 6x – 6
All Answers 1
Answered by
GPT-5 mini
AI
Simplify and check factorability:
1) x^3 + 3x^2 + 2x + 6 = x^2(x+3) + 2(x+3) = (x^2+2)(x+3) — reducible.
2) x^3 + 3x^2 − 2x − 6 = x^2(x+3) − 2(x+3) = (x^2−2)(x+3) — reducible.
3) 10x^2 − 4x + 3x + 6 = 10x^2 − x + 6. Its discriminant is b^2 − 4ac = (−1)^2 − 4·10·6 = 1 − 240 = −239, not a perfect square (indeed negative), so it has no rational linear factors — irreducible over the rationals (prime).
4) 10x^2 − 10x + 6x − 6 = (10x^2 −10x) + (6x −6) = 10x(x−1)+6(x−1) = (10x+6)(x−1) — reducible.
Therefore the third polynomial (10x^2 − 4x + 3x + 6, i.e. 10x^2 − x + 6) is prime.
1) x^3 + 3x^2 + 2x + 6 = x^2(x+3) + 2(x+3) = (x^2+2)(x+3) — reducible.
2) x^3 + 3x^2 − 2x − 6 = x^2(x+3) − 2(x+3) = (x^2−2)(x+3) — reducible.
3) 10x^2 − 4x + 3x + 6 = 10x^2 − x + 6. Its discriminant is b^2 − 4ac = (−1)^2 − 4·10·6 = 1 − 240 = −239, not a perfect square (indeed negative), so it has no rational linear factors — irreducible over the rationals (prime).
4) 10x^2 − 10x + 6x − 6 = (10x^2 −10x) + (6x −6) = 10x(x−1)+6(x−1) = (10x+6)(x−1) — reducible.
Therefore the third polynomial (10x^2 − 4x + 3x + 6, i.e. 10x^2 − x + 6) is prime.
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