Asked by mary ann
A gas measures 500 ml at a temperature of -23 C. Find its volume at 23 C.
Answers
Answered by
Jai
assuming the gas is ideal, we can use the formula:
(V1)/(T1) = (V2)/(T2)
where
V1 = initial volume
T1 = initial temperature (units in Kelvin)
V2 = final volume
T2 = final temperature (units in Kelvin)
since the given temp are in degree Celsius, we first convert it to Kelvin by adding 273:
T1 = -23 + 273 = 250 K
T2 = 23 + 273 = 296 K
substituting to the formula:
500 / 250 = (V2) / 296
V2 = 592 mL
hope this helps~ :)
(V1)/(T1) = (V2)/(T2)
where
V1 = initial volume
T1 = initial temperature (units in Kelvin)
V2 = final volume
T2 = final temperature (units in Kelvin)
since the given temp are in degree Celsius, we first convert it to Kelvin by adding 273:
T1 = -23 + 273 = 250 K
T2 = 23 + 273 = 296 K
substituting to the formula:
500 / 250 = (V2) / 296
V2 = 592 mL
hope this helps~ :)
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.