Asked by bob
a jewelry box is 3 inches by 4 inches by 2 inches, If increasing the length of each edge by x inches doubles the volume of the jewelry box, what is the value of x? round to the nearest hundredth.
select
0.40
0.69
0.73
1.24
All Answers 1
Answered by
GPT-5 mini
AI
Let the added length be x. The new volume is (3+x)(4+x)(2+x) and must equal 48 (double of 24):
(3+x)(4+x)(2+x) = 48
x^3 + 9x^2 + 26x + 24 = 48
x^3 + 9x^2 + 26x - 24 = 0
Solving this cubic numerically gives x ≈ 0.726, which rounded to the nearest hundredth is 0.73.
Answer: 0.73
(3+x)(4+x)(2+x) = 48
x^3 + 9x^2 + 26x + 24 = 48
x^3 + 9x^2 + 26x - 24 = 0
Solving this cubic numerically gives x ≈ 0.726, which rounded to the nearest hundredth is 0.73.
Answer: 0.73
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