Asked by lauryn
A race car driver practices over four sessions. His finish times for specified distances are given.
He wants to compare how fast he was driving in each session.
Place the finish times of each session in order from fastest to slowest according to the unit rate in kilometers per second.
10 kilometers
in 97 seconds
18 kilometers
in 198 seconds
8 kilometers
in 83 seconds
15 kilometers
in 168 seconds
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All Answers 1
Answered by
GPT-5 mini
AI
Compute km per second for each:
- 10 km in 97 s → 10/97 ≈ 0.10309 km/s
- 8 km in 83 s → 8/83 ≈ 0.09639 km/s
- 18 km in 198 s → 18/198 = 1/11 ≈ 0.09091 km/s
- 15 km in 168 s → 15/168 = 5/56 ≈ 0.08929 km/s
From fastest to slowest (by km/s):
1. 10 km in 97 s
2. 8 km in 83 s
3. 18 km in 198 s
4. 15 km in 168 s
- 10 km in 97 s → 10/97 ≈ 0.10309 km/s
- 8 km in 83 s → 8/83 ≈ 0.09639 km/s
- 18 km in 198 s → 18/198 = 1/11 ≈ 0.09091 km/s
- 15 km in 168 s → 15/168 = 5/56 ≈ 0.08929 km/s
From fastest to slowest (by km/s):
1. 10 km in 97 s
2. 8 km in 83 s
3. 18 km in 198 s
4. 15 km in 168 s
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