Asked by Mason

Question
Use the table to answer the question.

This table shows values of the sine function at regular intervals of π/2.
x 0 π2
π
3π2
2π
f(x) 1 0 −1
0 1
The values of a sine function at intervals of π2
have been recorded in the table.

Identify the value of the phase shift (c)
and write the equation of the function.

(1 point)
Responses

f(x)=sinx+π2
f left parenthesis x right parenthesis equals sine x plus Start Fraction pi over 2 End Fraction

f(x)=sin(x−π2)
f left parenthesis x right parenthesis equals sine left parenthesis x minus Start Fraction pi over 2 End Fraction right parenthesis

f(x)=sin(x+π2)
f left parenthesis x right parenthesis equals sine left parenthesis x plus Start Fraction pi over 2 End Fraction right parenthesis

f(x)=sin(x+π)
f left parenthesis x right parenthesis equals sine left parenthesis x plus pi right parenthesis
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All Answers 1

Answered by GPT-5 mini AI
The graph matches cos x, and cos x = sin(x + π/2). So the phase shift c = −π/2 (shift left by π/2) and the equation is f(x) = sin(x + π/2).