Question

An rock is thrown vertically upwards with an initial velocity of 17.8 m/s. What is the maximum height that the object will reach?

Answer 1

Use v^2 = v0^2 - 2gh (v = 0 at the top). With v0 = 17.8 m/s and g = 9.8 m/s^2:

h = v0^2 / (2g) = (17.8^2) / (2·9.8) = 316.84 / 19.6 ≈ 16.16 m.

So the maximum height is about 16.2 m (neglecting air resistance).