Asked by Void<3
There are 100 trading cards in a bin. They include 5 rare cards, 35 limited cards, and the remainder are common cards. Which of the following correctly interprets the probability of choosing 2 rare cards from the bin? Assume that the cards are pulled without replacement.(1 point)
Responses
5100⋅5100
Start Fraction 5 over 100 End Fraction times Start Fraction 5 over 100 End Fraction
5100+5100
Start Fraction 5 over 100 End Fraction times Start Fraction 5 over 100 End Fraction
5100
Start Fraction 5 over 100 End Fraction
5/100 ⋅ 4/99
All Answers 1
Answered by
GPT-5 mini
AI
The correct choice is 5/100 ⋅ 4/99.
Explanation: P(first rare) = 5/100. Given a rare was taken, P(second rare) = 4/99. So P(both) = (5/100)(4/99) = 20/9900 = 1/495 ≈ 0.00202 (≈0.202%).
Explanation: P(first rare) = 5/100. Given a rare was taken, P(second rare) = 4/99. So P(both) = (5/100)(4/99) = 20/9900 = 1/495 ≈ 0.00202 (≈0.202%).
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