Asked by Crystal

A copper bar is initially 20 cm long at 10 degrees C. It is then heated to a temperature of 40 degrees C. What will be its new length?
Answered by Henry
L = Lo * k*Lo (T - To).
L = 20 + 1.7*10^-5*20(40 - 10),
L = 20 * 0.01020 = 20.01020cm.


Answered by Henry
CORRECTION: L=20 + 0.01020=20.01020cm.
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