Question

Question 1


Which similarity criterion proves the two triangles above are similar?

(1 point)
Responses

AAS~
AAS~

SAS~
SAS~

SSS~
SSS~

AA~
AA~
Question 2
Explain your reasoning by proving the answer above and show your work. You may type it out or upload a picture. You must fully explain and show all work in order to receive full credit. (3 points)
0 / 10000 Word Limit
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Answer 1

I don't see the diagram, so I can't definitively pick which criterion applies. Please upload the picture or describe the given information (angle measures, any parallel lines, side lengths, etc.).

To help you quickly finish the problem once you upload/describe it, here are the short checklists and a ready-to-use proof template for each similarity criterion:

How to choose the right criterion
- AA (Angle–Angle): If you can show two pairs of corresponding angles are equal (often by given angle measures, vertical angles, or corresponding/alternate interior angles from parallel lines), the triangles are similar.
- SAS (Side–Angle–Side similarity): If two pairs of corresponding sides are in proportion and the included angles are equal, use SAS~.
- SSS (Side–Side–Side similarity): If all three pairs of corresponding sides are proportional, use SSS~.
- AAS (Angle–Angle–Side): If two angles and a non-included side are given in a way that shows similarity; note AAS is essentially AA for similarity (two angles suffice), but sometimes problems phrase it as AAS when a side is also referenced.

Proof template (use the statements that match the figure)
1. Identify and mark corresponding angles/sides on the diagram.
2. Show the first equality:
- e.g., ∠A = ∠D because they are corresponding/vertical/etc.
3. Show the second equality:
- e.g., ∠B = ∠E because they are corresponding/alternate interior/ given.
4. Conclude: Since two pairs of corresponding angles are equal, triangles ABC and DEF are similar by AA~.
5. (Optional) State the correspondence and side ratios: AB/DE = BC/EF = AC/DF.

Example (if there are parallel lines)
- Given line l ∥ line m, and transversal creates ∠1 and ∠4 as alternate interior angles → ∠1 = ∠4.
- Also vertical angles give ∠2 = ∠5.
- Thus two angles equal → triangles similar by AA.

If you upload the diagram or tell me the given angle/side relationships, I will write the exact, fully explained proof and pick the correct criterion.