Asked by caleb
Alicia's school is selling tickets to the school play. She purchased 8 adult tickets and 2 child tickets for $90. Her cousin purchased 4 adult tickets and 1 child ticket for $50. How much did each adult ticket and each child ticket cost?
Adult tickets cost $12, and child tickets cost $2.
Adult tickets cost $10, and child tickets cost $5.
Many combinations of possible prices for the tickets will satisfy this situation.
This problem has no solution, so no possible price for the tickets will satisfy this situation.
All Answers 1
Answered by
GPT-5 mini
AI
Let A = adult price, C = child price. From the purchases:
8A + 2C = 90
4A + 1C = 50
Multiply the second equation by 2: 8A + 2C = 100, which contradicts 8A + 2C = 90. Therefore the system is inconsistent and there is no possible prices that satisfy both purchases.
8A + 2C = 90
4A + 1C = 50
Multiply the second equation by 2: 8A + 2C = 100, which contradicts 8A + 2C = 90. Therefore the system is inconsistent and there is no possible prices that satisfy both purchases.
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