Question

On a coordinate plane, a line goes through (negative 3, 2) and (0, 1). A point is at (3, 4).
What is the equation of the line that is perpendicular to the given line and passes through the point (3, 4)?

y = –One-thirdx + 5
y = –One-thirdx + 3
y = 3x + 2
y = 3x − 5

Answer 1

First line slope = (1 − 2)/(0 − (−3)) = −1/3.
Perpendicular slope = 3. Through (3,4): y − 4 = 3(x − 3) → y = 3x − 5.

Answer: y = 3x − 5.