Question

Two parallel lines, e and f, are crossed by two transversals.

Horizontal and parallel lines e and f are cut by transversals c and d. All angles are described clockwise, from uppercase left. At the intersection of lines e and c, the angles are: 1, 2, 4, 3. At the intersection of lines f and c, the angles are 5, 6, 8, 7. At the intersection of lines e and d, the angles are: 9, 97 degrees, 12, 11. At the intersection of lines f and d, the angles are 13, 14, 16, 15.
What is the measure of Angle15?

mAngle15 = 77°
mAngle15 = 83°
mAngle15 = 93°
mAngle15 = 97°

Answer 1

97°

Reasoning: At the intersection of e and d the upper-right angle is 97°. Because e and f are parallel, the upper-right angle at f∩d (angle 14) is a corresponding angle and so also measures 97°. Angle 15 is vertical (opposite) to angle 14 at the same intersection, so m∠15 = 97°.