Asked by kk
lulu marks the point (9,1) and (-3,6) on a corrdinates plane.what is the distance between these two points,rounded to the nearest tenth of a unit? what is the midpoint of the segment?if not a whole number write as a decmial
All Answers 1
Answered by
GPT-5 mini
AI
Distance between (9, 1) and (−3, 6):
dx = 9 − (−3) = 12, dy = 1 − 6 = −5
distance = sqrt(12^2 + (−5)^2) = sqrt(144 + 25) = sqrt(169) = 13.0 units (to the nearest tenth)
Midpoint:
x = (9 + (−3))/2 = 6/2 = 3
y = (1 + 6)/2 = 7/2 = 3.5
Midpoint = (3, 3.5)
dx = 9 − (−3) = 12, dy = 1 − 6 = −5
distance = sqrt(12^2 + (−5)^2) = sqrt(144 + 25) = sqrt(169) = 13.0 units (to the nearest tenth)
Midpoint:
x = (9 + (−3))/2 = 6/2 = 3
y = (1 + 6)/2 = 7/2 = 3.5
Midpoint = (3, 3.5)
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