Question

Quadrilateral ABCD is transformed to A'B'C'D'.

The quadrilateral A-B-C-D has A at (3, 3), B at (6, 3), C at (4, 1), and D at (1, 1). The quadrilateral A prime-B prime-C prime-D prime has A prime at (-3, 0), B prime at (0, 0), C prime at (-2, -2), and D prime at (-5, -2).

Which rule describes this transformation?

A.
(
x
,
y
)
→
(
x
−
3
,
y
−
6
)

B.
(
x
,
y
)
→
(
x
−
6
,
y
−
3
)

C.
(
x
,
y
)
→
(
x
+
6
,
y
+
3
)

D.
(
x
,
y
)
→
(
x
+
3
,
y
+
6
)

Answer 1

B. The translation is (x, y) → (x − 6, y − 3).

Check: A(3,3) → (−3,0), B(6,3) → (0,0), C(4,1) → (−2,−2), D(1,1) → (−5,−2).