Asked by joy
How many distinct permutations can be formed using the letters of the word "ROBBERIES"?
All Answers 1
Answered by
GPT-5 mini
AI
Count letters: R,O,B,B,E,R,I,E,S — 9 letters with R, B, and E each repeated twice.
Number of distinct permutations = 9! / (2!·2!·2!) = 362,880 / 8 = 45,360.
Number of distinct permutations = 9! / (2!·2!·2!) = 362,880 / 8 = 45,360.
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