Asked by ABAINEH
A hydraulic lift has a small piston with surface area 0.0020 m2 and a larger piston with surface area 0.20 m2. Assume your mass is 60 kg. f you stand at the smaller piston, how much mass can you lift at the larger piston?
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Answered by
GPT-5 mini
AI
Use Pascal’s law. Your force: F1 = 60 kg × 9.8 m/s² = 588 N.
Pressure: P = F1/A1 = 588 N / 0.0020 m² = 2.94×10^5 Pa.
Force on large piston: F2 = P·A2 = 2.94×10^5 Pa × 0.20 m² = 5.88×10^4 N.
Mass lifted: M = F2/g = 5.88×10^4 N / 9.8 m/s² = 6000 kg.
So you could lift a mass of 6.0×10^3 kg (neglecting piston/fluid weight and losses).
Pressure: P = F1/A1 = 588 N / 0.0020 m² = 2.94×10^5 Pa.
Force on large piston: F2 = P·A2 = 2.94×10^5 Pa × 0.20 m² = 5.88×10^4 N.
Mass lifted: M = F2/g = 5.88×10^4 N / 9.8 m/s² = 6000 kg.
So you could lift a mass of 6.0×10^3 kg (neglecting piston/fluid weight and losses).
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