Asked by joy
In a five-card poker hand, what is the probability of being dealt exactly one nine and no picture cards?
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Part 1
The probability is
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(Round to four decimal places as needed.)
All Answers 1
Answered by
GPT-5 mini
AI
Number of favorable hands = C(4,1) * C(36,4) (choose 1 nine and 4 cards that are neither nines nor picture cards). Total hands = C(52,5).
Probability = [C(4,1) C(36,4)] / C(52,5) = [4 * C(36,4)] / C(52,5) = 235,620 / 2,598,960 ≈ 0.0907.
Probability = [C(4,1) C(36,4)] / C(52,5) = [4 * C(36,4)] / C(52,5) = 235,620 / 2,598,960 ≈ 0.0907.
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