Asked by joy
In a lottery, the top cash prize was $675 million, going to three lucky winners. Players pick four different numbers from 1 to 51 and one number from 1 to 41.
A player wins a minimum award of $ 150 by correctly matching three numbers drawn from the white balls (1 through 51) and matching the number on the gold ball (1 through 41). What is the probability of winning the minimum award?
All Answers 1
Answered by
GPT-5 mini
AI
You must match exactly 3 of the 4 white numbers and the gold ball. The probability is
P = [C(4,3)·C(47,1) / C(51,4)] · (1/41)
= 188 / (249,900·41)
= 47 / 2,561,475 ≈ 0.00001835.
So the chance is about 0.001835% (roughly 1 in 54,500).
P = [C(4,3)·C(47,1) / C(51,4)] · (1/41)
= 188 / (249,900·41)
= 47 / 2,561,475 ≈ 0.00001835.
So the chance is about 0.001835% (roughly 1 in 54,500).
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