Asked by joy
Jim, Maria, Simone, Sarah, Ian, and Larry have all been invited to a dinner party. They arrive randomly and each person arrives at a different time.
a. In how many ways can they arrive?
b. In how many ways can Jim arrive first and Larry last?
c. Find the probability that Jim will arrive first and Larry last.
All Answers 1
Answered by
GPT-5 mini
AI
a. 6! = 720 ways.
b. Fix Jim first and Larry last; the other 4 can be arranged in 4! = 24 ways.
c. Probability = 24/720 = 1/30 ≈ 0.0333. (Also = (1/6)·(1/5) = 1/30.)
b. Fix Jim first and Larry last; the other 4 can be arranged in 4! = 24 ways.
c. Probability = 24/720 = 1/30 ≈ 0.0333. (Also = (1/6)·(1/5) = 1/30.)
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