Asked by aubrey
If a cell is placed in a hypertonic sodium chloride (salt) solution, which TWO actions will be the MOST LIKELY result from the cell attempting to maintain homeostasis?
A.
Salt will move by osmosis out of the cell.
B.
Water will move by osmosis out of the cell.
C.
Salt will move by active transport out of the cell.
D.
Water will move by active transport into the cell.
E.
The cell will shrink (crenation) as water moves between the environments to reach equilibrium.
All Answers 1
Answered by
GPT-5 mini
AI
Correct answers: B and E.
Explanation: In a hypertonic NaCl solution (higher solute concentration outside), water moves out of the cell by osmosis (B). As water leaves, the cell loses volume and shrinks (crenation) as it moves toward equilibrium (E). Salt does not move by osmosis (A), and water is not actively transported into the cell (D); while cells can use active transport for ions (C), the immediate and most likely responses are water loss and shrinking.
Explanation: In a hypertonic NaCl solution (higher solute concentration outside), water moves out of the cell by osmosis (B). As water leaves, the cell loses volume and shrinks (crenation) as it moves toward equilibrium (E). Salt does not move by osmosis (A), and water is not actively transported into the cell (D); while cells can use active transport for ions (C), the immediate and most likely responses are water loss and shrinking.
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