Question

Segment EF is shown on the graph.


What is the x-coordinate of the point that divides EF into a 2:3 ratio?

–3.8
–3.6
1.2
1.4

Answer 1

Use the section (weighted average) formula. If EP:PF = 2:3, the x-coordinate is (3x_E + 2x_F)/5. From the graph x_E = −5 and x_F = −2, so x = (3(−5)+2(−2))/5 = (−15−4)/5 = −19/5 = −3.8.

Answer: −3.8