Question

On a coordinate plane, a line goes through (negative 4, 4) and (4, negative 2). A point is at (6, 0).
What is the equation of the line that is perpendicular to the given line and has an x-intercept of 6?

y = –Three-fourthsx + 8
y = –Three-fourthsx + 6
y = Four-thirdsx – 8
y = Four-thirdsx – 6

Answer 1

Slope of given line = (−2 − 4)/(4 − (−4)) = −6/8 = −3/4.
Perpendicular slope = 4/3. Through (6,0): y = (4/3)(x − 6) = (4/3)x − 8.

Answer: y = Four-thirds x − 8.