Question

last three.JPG
How long was the ball in the air?

Group of answer choices

5.71 s

3.90 s

4.18 s

8.78 s

Answer 1

I can't see the image you mentioned — could you re-upload last three.JPG or type the problem text (launch speed, angle, heights, or a diagram with numbers)?

While you do that, here are the quick ways to get the time-in-air depending on the problem type:

1) If the ball is launched and lands at the same height:
- vertical component v0y = v0 * sin(theta)
- total time T = 2·v0y / g = 2·v0·sin(theta) / 9.8 (s)

2) If the ball is launched from height y0 and lands at a different height (solve the vertical motion):
- y(t) = y0 + v0y·t − 0.5·g·t^2
- set y(t) = landing height (often 0) and solve the quadratic for t; the positive root is
t = [v0y + sqrt(v0y^2 + 2 g y0)] / g (if landing height = 0)

3) If you know horizontal distance x and horizontal speed v0x:
- time T = x / v0x

Tell me the numbers (v0, angle, initial height, landing height, or horizontal distance) or re-upload the image and I’ll compute which of the choices is correct.