Question

1d motion-1.JPG
How tall is the cliff?

Group of answer choices

0.36 m

6708.1 m

68.91 m

391.8 m

Answer 1

I can’t see the image you uploaded. Please either re-upload it or type the problem text / the numbers shown (initial velocities, angles, times, horizontal distance, etc.).

Meanwhile, here are the steps you need so you (or I) can pick the correct choice:

1) If the object is dropped (initial vertical speed = 0):
height = (1/2) g t^2
where g ≈ 9.8 m/s^2 and t is the time to hit the ground.

2) If the object is thrown horizontally with speed v_x and lands a horizontal distance x from the cliff:
t = x / v_x
then height = (1/2) g t^2.

3) If the object is launched at an angle with initial speed v0 and angle θ:
vertical component v0y = v0 sinθ
height (vertical displacement after time t) = v0y t + (1/2) g t^2
(use the appropriate sign convention for g and displacement).

If you give me the numbers shown in the diagram (time, horizontal range, initial speed/angle), I’ll compute the cliff height and pick the correct choice. If you want, paste the image text or a clear description of the diagram.