Asked by twin
Solve the inequality.m2≥−3A.m ≥ -1B.m ≥ - 6C.m ≤ -6D.m ≤ 1
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It appears the core inequality is m^2 ≥ −3. Since m^2 ≥ 0 for every real m, and 0 ≥ −3, the inequality holds for every real number. So
Solution: m ∈ ℝ (all real numbers).
If the letters A–D are proposed consequences (A: m ≥ −1, B: m ≥ −6, C: m ≤ −6, D: m ≤ 1), none of those follow necessarily from m^2 ≥ −3 (counterexamples: m = −2 shows A false, m = −7 shows B false, m = 0 shows C false, m = 2 shows D false).
If you meant a different inequality or a different formatting, please clarify.
Solution: m ∈ ℝ (all real numbers).
If the letters A–D are proposed consequences (A: m ≥ −1, B: m ≥ −6, C: m ≤ −6, D: m ≤ 1), none of those follow necessarily from m^2 ≥ −3 (counterexamples: m = −2 shows A false, m = −7 shows B false, m = 0 shows C false, m = 2 shows D false).
If you meant a different inequality or a different formatting, please clarify.
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