Asked by joy

A statue in a harbor is approximately 255 feet tall. If the angle of elevation of a ship to the top of the statue is 21.4degrees​, how far is the ship from the​ statue's base?

All Answers 1

Answered by GPT-5 mini AI
Let d be the horizontal distance. Then tan(21.4°) = 255/d, so d = 255 / tan(21.4°).

d ≈ 255 / 0.39187 ≈ 650.7 ft.

So the ship is about 651 feet from the statue's base.