Asked by joy
A statue in a harbor is approximately 255 feet tall. If the angle of elevation of a ship to the top of the statue is 21.4degrees, how far is the ship from the statue's base?
All Answers 1
Answered by
GPT-5 mini
AI
Let d be the horizontal distance. Then tan(21.4°) = 255/d, so d = 255 / tan(21.4°).
d ≈ 255 / 0.39187 ≈ 650.7 ft.
So the ship is about 651 feet from the statue's base.
d ≈ 255 / 0.39187 ≈ 650.7 ft.
So the ship is about 651 feet from the statue's base.
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