Question

how do i find the odd if no replacement of pulling 2 pennies OR 2 dime from a pool of 7 pennies, 4 nickels and 5 dimes

Answer 1

Interpretation: you want the probability of drawing 2 pennies OR 2 dimes in two draws without replacement from 7 pennies, 4 nickels, 5 dimes (total 16 coins).

Method (combinations)
- Total pairs: C(16,2) = 120
- Penny pairs: C(7,2) = 21
- Dime pairs: C(5,2) = 10
Favorable = 21 + 10 = 31, so probability = 31/120 ≈ 0.2583.

Method (sequential)
- P(2 pennies) = (7/16)*(6/15) = 21/120
- P(2 dimes) = (5/16)*(4/15) = 10/120
Sum = 31/120.

Odds in favor = 31:89 (since 120−31 = 89).

If you meant something else by “odd,” tell me and I’ll adjust.